(0.008)^(2x-1)+5^(3/2)=125

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Solution for (0.008)^(2x-1)+5^(3/2)=125 equation: 



(0.008)^(2x-1)+5^(3/2)=125

We move all terms to the left:

(0.008)^(2x-1)+5^(3/2)-(125)=0

determiningTheFunctionDomain
(0.008)^(2x-1)-125+5^(3/2)=0

We add all the numbers together, and all the variables

(0.008)^(2x-1)-125+5^(+3/2)=0

We multiply all the terms by the denominator


((0.008)^(2x-1))*2)-125*2)+5^(+3=0

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